XLVI. Quaestionum Petronianarum specimen novissimum

Unm - Pnm Statewide Mathematics Contest Xlvi - Solutions

The question is to find 2A+H +N + S. If we add the first and the third equations in the system and subtract the second equation from the result we obtain 2A+H +N + S = 21 + 18− 25 = 14. 2. If f(x) = x + 6x + 12x+ 6, solve the equation f(f(f(x))) = 0. Answer: Note that f(x) = (x + 2) − 2. Thus f(f(x)) = ((x + 2) − 2 + 2) − 2 = (x + 2) − 2 and f(f(f(x))) = ( (x+ 2) − 2 + 2 )3 − 2 = (x+ 2) − 2. So...

International Union of Pharmacology. XLVI. G protein-coupled receptor list.

NC-IUPHAR (International Union of Pharmacology Committee on Receptor Nomenclature and Drug Classification) and its subcommittees provide authoritative reports on the nomenclature and pharmacology of G protein-coupled receptors (GPCRs) that summarize their structure, pharmacology, and roles in physiology and pathology. These reports are published in Pharmacological Reviews (http://www.iuphar.org...

Georeferencing Animal Specimen Datasets

For biodiversity research, the field of study that is concerned with the biological diversity of our planet, it is of utmost importance that the location of an animal specimen find is known with high precision. Due to specimens often having been collected over the course of many years, their accompanying geographical data is often ambiguous or may be very imprecise. In this contribution, we det...

Controlled environment specimen transfer.

Specimen transfer under controlled environment conditions, such as temperature, pressure, and gas composition, is necessary to conduct successive complementary in situ characterization of materials sensitive to ambient conditions. The in situ transfer concept is introduced by linking an environmental transmission electron microscope to an in situ X-ray diffractometer through a dedicated transmi...

Exhibition of Specimen